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M12. Methanol, CH3OH, has been considered as a possible fuel. Consider its oxidation: 2 CH3OH(1) + 3 O2(g) → 2 CO2(g) + 4H2O(
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Maximum work that can be obtained = 343 kJ

2 CH3 OH (l) + 302(9) — 2609) + 4H20 (g) 49. = -1372 kJ/mol Ara for 0.50 methand 0.50 mol CH₃OH . -1372 kJ/mol 2 mol CH₃OH =

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