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How many moles of gaseous boron trifluoride, BF3, are contained in a 434.10-mL bulb at 788.0...

How many moles of gaseous boron trifluoride, BF3, are contained in a 434.10-mL bulb at 788.0 K if the pressure is 1.220 torr? How many grams of BF3? Which law is this?
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Answer #1

Sol na PV Guiven that - (v) Volume of BF3 = 484.10 me 20:43412 (1) Temperature = 788K Bessine (P) = 1.220 tory As we know tha

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