Question

The manager of a paint supply store wants to estimate the actual amount of paint contained in 1-galion cans purchased from a nationally known manufacturer. The manufacturer's specifications state that the standard deviation of the amount of paint is equal to 0.01 gallon. A random sample of 50 cans is selected, and the sample mean amount of paint per 1-gallon can is 0.987 gallon. Complet parts (a) through (d). a Construct a 99% confidence interval estimate for the population mean amount of paint included in a 1-gallon can. (Round to five decimal places as needed.)

Answer 1

Given that, sample size ( n ) = 50

sample mean $(\bar x)$ = 0.987 gallon

population standard deviation $(\sigma)$ = 0.01galllon

confidence level = 99% That is c = 0.99

Using TI-84 calculator we get, 99% confidence interval estimate of the poulation mean $(\mu)$ amount of paint included in a 1-gallon can is (0.98336, 0.99064)

$0.98336 \leq \mu \leq 0.99064$

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