here,
a)
for m2
as the mass m2 is in equilibrium
T = m2 * g .....(1)
b)
the acceleration of m1 is ac
using Newton's second law
m1 * ac = T
m1 * v^2 /R = T ....(2)
c)
from (1) and (2)
m1 * v^2 / R = m2 * g
v = sqrt(m2 * g * R /m1)
the speed of puck is v = ( sqrt(gR m2 /m1))
5. 12 points PSE6 6.P058 My Notes An air puck of mass m1 is tied to a string and allowed to revolve in a circle of radius R on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a counterweight of mass m2 is tied to it (Fig. P6.58). The suspended object remains in equilibrium while the puck on the tabletop revolves. Answer the following questions by writing...
An air puck of mass 0.23 kg is tied to a string and allowed to revolve in a circle of radius 1.2 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 0.9 kg is tied to it. The suspended mass remains in equilibrium while the puck on the tabletop revolves. a) What is the tension in the string? (b) What is the force...
An air puck of mass 0.200 kg is tied to a string and allowed to revolve in a circle of radius 1.03 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 1.22 kg is tied to it as seen in the figure below. The suspended mass remains in equilibrium while the puck on the tabletop revolves. What is the tension in the string?...
An air puck of mass 0.18 kg is tied to a string and allowed to revolve in a circle of radius 1.1 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 1.3 kg is tied to it. The suspended mass remains in equilibrium while the puck on the tabletop revolves (a) What is the tension in the string? (6) What is the force...
An air puck of mass 0.230 kg is tied to a string and allowed to revolve in a circle of radius 1.17 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of 1.03 kg is tied to it as seen in the figure below. The suspended mass remains in equilibrium while the puck on the tabletop revolves. What is the tension in the string?...
27. An air puck of mass m, = 0.25 kg is tied to a string and allowed to revolve in a circle of radius R = 1.0 m on a frictionless hori- zontal table. The other end of the string passes through a hole in the center of the table, and a mass of m, = 1.0 kg is tied to it (Fig. P7.27). The suspended mass remains in equilibrium while the puck on the tabletop revolves. (a) What is...
Anar puck of mass my is tied to a string and allowed to revolve in a circle of radius Rona horizontal, frictionlesstabile The per end of the string passes through a small hole in the center of the table, and an object of mass my is tied to it (see fire). The suspended object remains in equilibrium while the puck on the tabletop revolves. and the radius of th. --50 il (a) The tangential a=rar (b) The final tangential (*)...
Course Contents> Set 03 (09/25 Tu 10 PM) Air puck on a table An air puck of mass 0.604 kg is tied to a string and allowed to revolve in a circle of radius 1.13 m on a frictionless horizontal table. in the fiqure. Timer□ Notes è Evaluate Feedback-Print The suspended mass remains in equilibrium while the puck on the tabletop revolves. What is the tension in the string? Submit Answer Tries 0/12 What is the magnitude of the force...
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FIGURE P6.20 An air puck of mass my is tied to a string and allowed to revolve in a radius hori- e ot On a zontal table. The other end of the string passes through a bole in the center of the table, and a mass r is tied to it (Fig. P6.38). The suspended mass re mains in equilibrium while the puck on...
A small object of mass m1 moves in a circular path of radius r on a frictionless horizontal tabletop. It is attached to a string that passes through a frictionless hole in the center of the table. A second object with a mass of m2 is attached to the other end of the string. Derive an expression for r in terms of m1, m2, and the time T for one revolution. (Use any variable or symbol stated above along with the...