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Question 1 Suppose two liquids (A and B) are mixed together and a phase diagram constructed for this real solution (shown in800 700 600 500 pA 400 (Pa) 300 200 100 0 0 0.2 0.6 0.8 0.4 XA

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Answer #1

(a)

Mole fraction is defined as the moles of the substance divided by the total moles present in the system.

Thus, let us consider a system having two species A and B.

So, according to definition of mole fraction:-

ng Mole fraction of B=- natno

Given that:-

n_A = Moles of A = 4.6 moles

n_B = Moles of B = 3.6 moles

Applying the values in the above equation as:-

3.6 3.6 Mole fraction of B=7 = 0.44 4.6 +3,6 =

Thus, the mole fraction of B = 0.44

(b)

From the graph, it is clearly stated that the real solution has the higher vapor pressure.

This state is known as non-ideal solutions having positive deviation. This occurs because the vapor pressure by each component is greater than what is being calculated by the Raoult’s law (ideal solutions).

Thus, the total vapor pressure curve of the system appears higher than the vapor pressure of the pure components.

This arises because the solute-solvent interactions in the system are weaker when compared to the solute-solute and solvent-solvent interactions in the system.

(c)

Considering, for a binary system involving two components A and B,

Mole fraction of B = 1 - Mole fraction of A

So, graph can be translated to:-

pB (Pa) / 1 0 0.2 0.4 0.6 0.8 0.8 0.8 0.6 0.4 0.2 0.2 0

As calculated above,

x_B = 0.44

So, from the graph:-

200 pB (Pa) 120 Pa 100 0.8 0.6 0.4 0.2

The partial pressure of B if the system is an ideal solution is 120 Pa.

(d)

As calculated above,

x_B = 0.44

So, from the graph:-

300 210 Pa 200 pB (P.) 1 0.8 0.6 0.40.4 0. 2 0

Since, it is between 220 and 200 Pa, the middle should be 210 Pa.

The partial pressure of B if the system is a real solution is 210 Pa.

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