Question

An object 1.50 cm high is placed a distance of 31.2 cm in front of a converging MIRROR having focal length 13.5 cm. a) Determine the image distance. b) Determine the magnification of the mirror b) Determine the image characteristics (real/virtual, upright/inverted, size). c) Draw an accurate ray diagram of this situation. d) If the object is moved to a distance of 15.8 cm from the mirror, determine the location of the image. e) At what distance from the mirror should the object be place to create an image with a magnification of -5.00?

Answer 1

we have the spherical mirror formulae 7 to 1 Given, u=-31.2an. ha - 1.50 cm for conversing foul Lagth f= - 13.5 cm. then, I- I - v 31.2 13.5 I Do 31.2 13.5 13.5-31.2 31-2x13.5 31.2x13.5 31.2 - 13.5 U -23.8 Cin. formed infront of V- >> image 3.8 cm, So the the conversing Mirror. from the definition of magnetication ma- 23.8 =-0.763 31.2 se the creage is inverted & real. 0 Image is real and invested. Р - PER Vio O a object distace. og= Image distace. PQ- oheet weight Palmaze height

de Aster moved the object 15.8cm, then u= - (31.2 +15.8). = - 41cm, thene - + - - h 47x13.5 4T-13.5 - = - 18,94 com. Image location. Given, m=-5.00, frown. 29 1 am van - $623.8)= -5.00 23-8 - U - - 4. 16 can.