Case 1:
P(Head in coin) = 1/2
(Two sides: Head & Tail. So, P(H) = 1/2)
Case 2:
P(less than 4 in 16 sided die) = 3/16
(Less than 4 are: 1, 2 and 3. So, P(Less than 4)= 3/16)
Case 3:
P(Number greater than 15 in roulette wheel) = 22/37
(Total numbers = 37. Numbers greater than 15 = 22. So, P(Number greater than 15) = 22/37)
So,
P(Head in coin AND Less than 4 in die AND Greater than 15 in Roulette wheel)= (1/2)X (3/16) X (22/37) = 66/1184=0.0557
So,
Answer is:
0.0557
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