/Users/neginalizadeh/Desktop/IMG_1404
2.JPG
Electric field due to charged rod E = 2 k lambda/r sin theta
= 2*9e9*1/0.5 * sin 45 degree
= 2.546*10^10 N/C Answer
/Users/neginalizadeh/Desktop/IMG_1404 2.JPG Figure 16-44 Problem 66 67. of 1.0 C evenly distributed throughout (Figure 16-45). What...
BACK Chapter 22, Problem 031 Your answer is partially correct. Try again In the figure a nonconducting rod of length L-8.46 cm has charge -q-4.36 fC uniformly distributed along its length. (a) What is the linear charge density of the rod? What are the (b) magnitude and (c) direction (positive angle relative to the positive direction of the x axis) of the electric field produced at point P, at distance a 15.2 cm from the rod? What is the electric...