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Question 2 2.1. 2.2. Explain why discounted cash flow (DCF)methods are regarded as superior to non DCF approaches to project
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2.1- Discounted cash flow method are considered as better methods over non discounted cash flow methods because discounted cash flow methods consider the risk due to inflation and time associated with the cash flow. Discounted cash flow method consider time value of money concepts to evaluate the performance of project while non discounted cash flow methods do not consider concept of time value of money.
2.2-
Year cost of gas consumption of old boiler over the years = current year consumption*(1+inflation rate) inflation rate =2% Annual saving from the use of new boiler =20% of the gas consumption of old boiler Accumulated annual savings Year Annual saving from the use of new boiler =20% of the gas consumption of old boiler present value factor = 1/(1+r)^n r =5% present value of annual savings = annual savings*present value factor at 5%
0 0 -2400 1 -2400
1 1250 250 250 1 250 0.952381 238.0952381
2 1275 255 505 2 255 0.907029 231.292517
3 1300.5 260.1 765.1 3 260.1 0.863838 224.6841594
4 1326.51 265.302 1030.402 4 265.302 0.822702 218.264612
5 1353.0402 270.60804 1301.01004 5 270.60804 0.783526 212.0284802
6 1380.101 276.020201 1577.030241 6 276.0202008 0.746215 205.9705236
7 1407.703 281.540605 1858.570846 7 281.5406048 0.710681 200.0856515
8 1435.8571 287.171417 2145.742263 8 287.1714169 0.676839 194.3689186
9 1464.5742 292.914845 254.2577375 amount to be recovered in year 10 =2400-2145.74 9 292.9148453 0.644609 188.8155209
10 1493.8657 298.773142 10 298.7731422 0.613913 183.4207918
11 1523.743 304.748605 11 304.748605 0.584679 178.1801977
12 1554.2179 310.843577 12 310.8435771 0.556837 173.0893349
13 1585.3022 317.060449 13 317.0604486 0.530321 168.1439254
14 1617.0083 323.401658 14 323.4016576 0.505068 163.3398132
15 1649.3485 329.869691 15 329.8696908 0.481017 158.6729614
16 1682.3354 336.467085 16 336.4670846 0.458112 154.1394482
17 1715.9821 343.196426 17 343.1964263 0.436297 149.735464
18 1750.3018 350.060355 18 350.0603548 0.415521 145.4573079
19 1785.3078 357.061562 19 357.0615619 0.395734 141.3013848
20 1821.014 364.202793 20 364.2027931 0.376889 137.2642024
Payback period = year before final year of recovery+(amount to be recovered in year 10/annual savings of year 10) 9+(254.2577/298.77) 9.85 Net present value =sum of present value of annual savings 1266.35
IRR Using IRR function in MS excel IRR(J850:J870) 10.20%C. - = New Microsoft Office Excel Worksheet (2) - Microsoft Excel Home Insert Page Layout Formulas Data Review View * Cut Cal
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