Solution)
Given,
Emissivity, E=0.35
Radius, r=0.19 m
Temerature t=273+24=297 K
We know, Power, P= sigma*E*A*T^4
Substitute values,
P=(5.67*10^-8)*(0.35)*(4pi*0.19^2)*(297)^4= 70.01 J/s (Ans)
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Part A How much power is radiated by a tungsten sphere (emissivity € = 0.35) of...
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