Question

A chemist carefully measures the amount of heat needed to raise the temperature of a 1.53 kg sample of a pure substance from -4.5 °C to 11.6 °C. The experiment shows that 60.1 kJ of heat are needed. What can the chemist report for the specific heat capacity of the substance? Be sure your answer has the correct number of significant digits.

Answer 1

ANSWER:-

Q=mcΔT

Q = mc Δ T , where Q is the symbol forheat transfer, m is the mass of the substance, and ΔT is the change in temperature. The symbol c stands for specific heat and depends on the material and phase.

So here in tjis qiestion c=Q/mΔT change in the tempreature = 116⁰c - (-4.5⁰c) = 120.5⁰ c that us 273+120.5 = 393.5K

m = 1.53 kg

Q= 60.1KJ =60.1x1000 J

C= 60.1x 1000/1.53x 393.5

C= 60.1x1000/602.055

C= 99.82J/k xKg