Question

4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml of H2SO4 is neutralized by 25 ml of 0.7 M NaOH. What is the molarity of H2SO4? Bonus Question: NaOH was standardized by titration against a standard acidic solution of potassium hydrogen phthalate (KHP). 0.4798 g of KHP were dissolved in 100 ml of water to prepare the standard KHP solution. a) What is the molar mass of KHP? you need to look up its formula and calculate its molar mass from the periodic table. b) If 45.22 ml of sodium hydroxide were required to neutralize the KHP solution, what is the molarity of NaOH? Show all your calculations.

Answer 1

(Dole 1 - Ans!! In this question we have given that vinegary is solution o E Lacetic acid. L such that acetic acid has 1:1 ratio when rocled with MODA__ _ d> Here we have to find out grams of aceas_aud present in vinegar a solution Molarity of acetic acid in Vinegar O SM. Molar mass of acetic acid = Gog/mol lie. Go gimol in 1ooo m = IM = 30 g/mol of Archie addin 1000m1 = 0.5M Then how much groms of acetic acid Lien 5 miwill be equivalent to ous M. det say it is thenX =80X 52 1000 - 150 de 1000 _X_2_0.15_g/mol -- form of acetic Hence: 015 almal aid in the given is present in tibration by Now if vinegar has a density rolg/mol le. total weight of vinegar for o.sm Coillibe20X101 = Bozg/mol Hence_.% Acetic aud in vinegar will be of % = 0.15 x 100 0.497 of acetic acid Essdained with CamScariner

> Here we know Loentealised by that soml of Masou is 25ml of o.7 M HODH & Now as 1.soy is diabasic acid contains Pets chance it will require twise atrength of Naon to neutralise H2sou Let Molarity of H₂SO4 = M, = x Volume of H₂SO4 = = 50m Molatity of Mall = M2.2009 0:35 M Volume of Haon = 25m) 2 . 2 . Then Mixv, = V2 M2 2 X 50 = 0' 35 X 25 _X =0.35 X25 50 X = 0.145 M Heno Molarity of tasou is o 175 m Thank you Stanned within Hetem Scanner