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Part A Use the data to find ΔH∘rxn and ΔS∘rxn for the reaction.<Chapter 18 Homework Exercise 18.79 37 of 37 > M Review Constants Periodic Table Consider the following reaction: H (9) + L (

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Answer #1
K lnK T (K) (1/T)
1.4×10-6 -13.48 150 0.0067
4.6×10-6 - 12.29 175 0.0057
3.6×10-2 -3.32 200 0.0050
1.1 0.095 225 0.0044
15.5 2.74 250 0.0040

Now plot of lnK vs (1/T) is

Intercept (a): 28.442502168257 Slope (b): -6529.7484822203 Regression line equation: y=28.442502168257- 6529.7484822203x 0 0

lnK = - \frac{\Delta H}{RT} + \frac{\Delta S}{R}

Slope = \frac{\Delta H}{R} = 6529.75

Or, \Delta H = R × 6529.75 = 8.314× 6529.75 = 54290 J = 54.29 KJ

Intercept = \frac{\Delta S}{R} = 28.44

\Delta S = 28.44 × R = 28.44 × 8.314 = 236.45 J/K

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