3)
Lets number the reaction as 1, 2, 3 from top to bottom
required reaction should be written in terms of other
reaction
This is Hess Law
required reaction can be written as:
reaction 3 = +0.5 * (reaction 1) -1 * (reaction 2)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = +0.5 * ΔHo rxn(reaction 1) -1 * ΔHo rxn(reaction 2)
= +0.5 * (67.0) -1 * (-56.0)
= 89.5 KJ
Answer: 89.5 KJ
Only 1 question at a time please
please help, i dont understand and need steps explainsd as well thank you Exercises: 3. Given...
please help I need help understanding, explain steps too, thank you 4. Given the following two thermochemical equations, determine the AHx,unknown. Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) AHørxn=-26.7 kJ CO(g) + 42 02(g) - CO2(g) AHºrx= -283.0 kJ 2 Fe(s) + 3/2 02(9) Fe2O3(s) AHºrxn unknown= ? 5. Calculate AHº for the reaction 2 C(s) + H2(g) – C2H2(g) Given the following data C2H2(g) + 5/202(g) → 2C02(g) + H20(C) C(s) + O2(g) → CO2(g) Hz(9)...
please help 4. You are given the following information. C (graphite) + O2 (g) - CO2 (g) CO(g) + 02 (9) - CO2 (g) Determine the standard enthalpy change for the reaction: C (graphite) + 02 (g) - CO(g) AH = - 393.5 kJ AH° = -283.0 kJ AHrxn = ?
2. Determine: 2 Fe2O3 (s) + 3 C(s) + 3 CO2 (g) + 4 Fe (s) Given: 2 Fe (s) + 3/2 O2 (g) → Fe2O3 (s) C(s) + 1/2 O2 (g) → CO (g) CO (g) + 1/2 O2 (g) → CO2 (g) AH = -822.2 kJ AH = -110.5 kJ AH = -283.0 kJ
5 Determine the standard enthalpy of formation of Fe2O3(s) given the thermochemical equations below. 2Fe(s) + 3/2 O2(g) → Fe2O3(s) AH(Fe2O3) = ? Fe(s) + 3 H2O() Fe(OH)3(s) + 3/2 H2(g) AH° = +160.9 kJ/mol-rxn H2(g) + 1/2O2(g) → H2O(1) A.H° = -285.8 kJ/mol-rxn Fe2O3(s) + 3 H2O(1) ► Fe(OH),(s) A,Hº +288.6 kJ/mol-rxn
15. Determine the standard enthalpy of formation of Fe2O3(s), 2Fe(s) + 1.5 02 (g) → Fe2O3(s) given the thermochemical equations below. (4 points) AFH° = +160.9 kJ/mol-rxn Fe(s) + 3 H20(8) - Fe(OH)3(s) + 3/2 H (9) H2(g) + 1/2 O2(g) → H2O(6) Fe2O3(s) + 3 H2O(0) - 2 Fe(OH)3(8) A-H° = -285.8 kJ/mol-rxn A,Hº = +288.6 kJ/mol-rxn
uations, calculate AH°rxn for the reaction: (3 marks) LFrom the following thermochemical eq So2(g)+NO2(8) SO3(8)+NO(g) 2 SO28)+02(8)-2SO3(8) 2N0(g) + O2(g. 2 NO2(g) A rxn--197.8 kJ Δ//orxn®-114, 14 kJ -SMB, eus e ,
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3.(15 pts) In each case, find the missing AH (kJ/mole) (a) If 2Al(s) + Fe2O3(s) - > Al2O3(s) + 2 Fe(s) AH -851.5kJ/mol then 1/8 Al2O3(s) + 1/4 Fe(s) ---> 1/4 Al(s) + 1/8 Fe2O3(s) AHan = ? (b) If Cao(s) + 3 C(s) --> CaC(s) + CO(g) AH -464.8 kJ/mol then 6 CaO(s) + 18 C(s) -> 6 CaC2(s) +6 CO(g) AH = ? (c) If N2(g) + 2 02(g) ---> N2O(g) and 2 NO2(g) ---> N2(g) + 2...
q#2 pressure? 103.5 g of NU2 is produced, now 463,3g & Abg Nor & Noa ANO(g) + O2(g) → 2NO2(g); AH = -114.4 kJ Imol Nos X-114.4 46g No Imall Noz of x-114.4K) = -501.5 2. If Fe2O3(s) + 3CO(g) 2Fe(s) + 3CO2(g); AH° = -26.8 kJ 13 FeO(s) + CO(g) Fe(s) + CO2(g); AH--16.5 kJ determine AH” for the following thermochemical equation. 63) Fe2O3(9)+ CO(g) – 2FeO(s) + CO2(8) ote 2 (s) + 300 lgl - 2Pels) + 3...
please help, explain steps I am very confused. thank you very much "" 9900 CU U UUUUTE Exercises: 1. When butane (C4H10) undergoes combustion, 2853.6 kJ of energy is released for every mole of butane consumed. The combustion reaction is as follows: _C4H10(0) + _ 02(g) → __CO2(g) +_ H20(0) AH°rxn = ? a. Balance the equation b. Determine the value for AHºnxn (be careful to make sure the value corresponds to the correct number of moles of C4H10). 2....