Given that,
mean = = 100
standard deviation = = 15
Using standard normal table,
P(Z > z) = 10%
= 1 - P(Z < z) = 0.10
= P(Z < z ) = 1 - 0.10
= P(Z < z ) = 0.9
Z=1.28
Using z-score formula
x = z +
x = 1.28*15+100
x=119
b) (6 points) Student scores from a high school on an IQ test are normally distributed...
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