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l Review What was Lewiss acceleration at t 4.20 s Careful measurements have been made of Olympic sprinters in the 100- Express your answer using four significant figures meter dash. A quite realistic model is that the sprinters velocity is givern by a(1-e) where t is in s·L4 is in m/s, and the constants a and b are characteristic of the sprinter. Sprinter Carl Lewiss run at the 1987 World Championships is modeled with a 11.81m/s and b 0.6887s1 im Submit PrewausAnswe Request Ans鯉! Incorrect; Try Again; 9 attempts remaining ▼ Part D Find an expression for the distance traveled at time t. Express your answer in terms of the variables a, b, and t r(t)- Submit Previous Answers Request Answer

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Answer #1

Since we know the velocity,we can figure out the acceleration simply by taking the derivative

ax =dvx/(dt)

In order to find the distance ,we need to integrate the velocity,remembering that lewis is at the origin x0 =0 at time t=0.

lst bt bt .J @_aebt)dt t -bt 11-31一に06,8和6) ico, 9 G92546 m let 6-6827 eohich is close but, abit too bož, Lets try

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