Question

sics for Scientists and Engineers 4th ed (1.pdi-Adobe Acrolst Reader Dc Window Help ools Giancoli Physics fo... x 93 1322 111% EXAMPLE 21-11 Long line of charge. Determine the magnitude of the electric field at any point P a distance x from the midpoint 0 of a very long line (a wire, say) of uniformly distributed positive charge, Fig. 21-29. Assume x is much smaller than the length of the wire, and let λ be the charge per unit length (C/m). APPROACH We set up a coordinate system so the wire is on the y axis with origin 0 as shown. A segment of wire dy has charge do - Ady. The field dE at point P due to this length dy of wire (at y) bas magnitude wtre ( y) as shown in Fig 21-29. The vector dE has components dEy and dEy as shown where dE -dE cos 8 and dEy dE sin. SOLUTION Because o is at the midpoint of the wire, the y component of E will there will be equal contributions to Ey fdE, from above and FIGURE 21-29 Example 21-11. below point 0 Thus we have A fcos 8 dy The integration here is over y, along the wire, with x treated as constant. We must now write e as a function of y, or y as a function of . We do the latter: since y xtan, then dyx de/cos 6. Furthermore, because cos θ = x/Vir+ア, then 1/(x1+y)-cos, e/r, and our integrand above is cos®)Xx de/cos eX(cose/x) cos de/x. Hence where we have assumed the wire is cxtremely long in both directions (y → is) which corresponds to the limits θ-tr/2. Thus the field near a long straight wire of uniform charge decreases inversely as the first power of the distance from the wire. NOTE This result, obtained for an infinite wire, is a good approximation for a wire of finite length as long as a is small compared to the distance of P from the ends of the wire. SECTION 21-7 Electric Field Calculations for Continuous Charge Distri 573 pe here to search
media%2F89a%2F89ad3296-c5b4-40b2-bc0e-e0
0 0
Add a comment Improve this question Transcribed image text
Answer #1

0.144 SİMB-D.989 O1 204 Sin e0111 (0,-3.9 41,2 Cese 2 29153-135 (sing-sin θ)= 399. 53125V/m 乙 --299 5 3.125 0.041-0.144 305 1 V/m 9.5315, 0.99 5 Ég = 0.0515please rate it up thanks :)

Add a comment
Know the answer?
Add Answer to:
sics for Scientists and Engineers 4th ed (1.pdi-Adobe Acrolst Reader Dc Window Help ools Giancoli Physics...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra...

    Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...

  • please answer all prelab questions, 1-4. This is the prelab manual, just in case you need...

    please answer all prelab questions, 1-4. This is the prelab manual, just in case you need background information to answer the questions. The prelab questions are in the 3rd photo. this where we put in the answers, just to give you an idea. Lab Manual Lab 9: Simple Harmonic Oscillation Before the lab, read the theory in Sections 1-3 and answer questions on Pre-lab Submit your Pre-lab at the beginning of the lab. During the lab, read Section 4 and...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT