Question

We sedi 6. Cisplatin was one of the first inorganic chemotherapy drugs developed. Displacement of a chloride ligand by water is necessary to convert the drug into its active form: HẠN NHỊ HO HẠN NH] CI' CI ci OH2 cisplatin Extensive studies have been conducted in order to determine the kinetics of this process in order to maximize the concentration of the active form of the drug in patients. From the following tabulated data, determine: k (M/min x 106) 9 cisplatino (M x 103) 6 12 24 h 30 18 36 T 45 a. The order of the b. The rate law for the reaction. Assume the order of the reaction in water is 0. What is the name of this approximation and why is it valid under the biological conditions that this drug is administered?

Answer 1

a. Order of the reaction can be determined from the experimental data

when we double the concentration of cis platin from 6 to 12 rate of reaction will also doubles from 9 to 18. This shows reaction is first order with respect to cis platin

hence order of reaction : 1

B. rate = k[cis-platin]¹ . since concentration of water is constant hence this does not appear i rate law. This is called pseudo-first order reaction

C. since it is a first order hence plot of rate v/s concentration will give a straight line with slope equal to k (rate constant

substrate(rate 6 rate 12 18 24 36 50 30 45 45 y1.5x 40 35 30 25 20 15 10 0 0 10 15 20 30 35 25 Ln

hence k = 1.5 min^-1

(D) For 1st order reaction half life does not depend on initial concentration

$t_{1/2} = \frac {0.693}{k}$

$t_{1/2} = \frac {0.693}{1.5}=0.462 min$

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