Question 7 (1 point) How many moles of H+ are in 120.0 mL of an HCl...

Question

Question

Answer 1

Answer #1

Mol of NaOH reacting = M(NaOH)*V(NaOH)

= 0.1100 M * 0.05146 L

= 5.66*10^-3 mol

For complete neutralisation,

Mol of HCl reacting = mol of NaOH reacting

= 5.66*10^-3 mol

So,

mol of H+ = 5.66*10^-3 mol

Answer: 5.66*10^-3 mol

Answer 2

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