T = tension force in the thread
m = mass of the bead = 0.018 g = 0.018 x 10-3 kg
= angle of thread with the vertical = 28 deg
Along the vertical direction , force equation is given as
T Cos = mg eq-1
Along the horizontal direction , force equation is given as
T Sin = Fe eq-2
dividing eq-1 by eq-2
T Cos/(T Sin ) = mg / Fe
Fe = mg tan
electric force between the beads is given as
Fe = k q2/r2
hence
k q2/r2 = mg tan
(9 x 109) q2/(0.04)2 = (0.018 x 10-3) (9.8) tan28
q = 4.1 x 10-9 C
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