Question

3. Use your textbook to determine the structure of D-Glucose and D-Idose. Are these molecules diastereomers or enatiomers. (Be sure to look up structures in books table of carbohydrates) Explain your choice. 4. Given a molecule of D-glucose and D-Fructose, how many membered ring will each monosaccharide form? Of the members (atoms) how many will be carbon and how many are oxygens for each? Finally, which oxygen is incorporated into the cyclic structure. 5. Show the oxidation (weak oxidizing agent) AND the reduction of D-Allose. (Two separate reactions). You must start a thread before you can read and reply to other threads

Answer 1

Question is solved using properties of carbohydrates.

solution- (6) Structure of D-Gelucose and D-idose is OH -Ho SH -on UC-u us o Ron os (OR on X Ron (6) CH2OH Congol D-belulose D-idose The configuration at position (5) is same in D-cilucose and D- 1 dloge but different at position (22 , (3), (4) • Hence these are diastereomers, they can not farm mieuwe image of each other g) open chain form of D-glucose and o- fumatore au as CHO gh-04 Hon ezo no HOH no TH LOW H OH -oh Chon Crook D-glucose D-fructose

After interamolecular Nucleophilic addition sceaction betwech Czo ya and C-5 drydroxy gf the cyclic structure farm as- COH CH₂OH c C oH 개 역에 HH OH H -D-Glucobesanese d-D-facetofuranse | 7 6 bie mbeced seing 5 carbon +1 Okyyen 75 membend sing 4 carbon & 1 oxygen - . In both structure oxygen of - on inceu posiated in cyllic stöuctwie gp at position -5 is 5- ton słowokuse of D-Allose in Bolal D-allonic acid —ои сува и Cuckoxidizing oxidation -oh иби kon anon noton weak oxidizing Pion WOH on agent anon Streuetune of D-allose - 55 ho HOM chqon a can not reduced by wstak oxidung

рои POH Nabha reduction no -OH 애 En20H си + tuott Dallose (product) D- Allital