Question

Calculate the molarity of each solution.

Part A

36.2 g of KCl in 0.885 L of solution

Express your answer using three significant figures.

____=M

Part B

62.3 g of C2H6O in 3.8 L of solution

Express your answer using two significant figures.

____=M

Part C

43.2 mg of KI in 106 mL of solution

Express your answer using three significant figures.

____=M

Answer 1

molaritef = Nemebes of mules of solelte o volume of solution in letre Nember of moles= mass ên grow Molas måss Past à Mass of Kce= 36240 ...- Molas mass ef kcl = 74.553/mol Menubes of miles of ked me to the = 0. 4856 mote volume of solution = 0.8852 Molaset= 00m = 05407 modl=0.5U87m - L 0.0051 ...36.29 2 mol moles mass of leto = 46 g/mol Neombs of moles of (2460 = tem tot 21-354 mol volume of solution = 3.8L modatie = "tes met 0.3863 M Past'c Mass of ki = 432 mg = 43.28=0.04 Moles mass of KI = 166 g/mol 1000 Wass C CamScanner

Nemubes of moles of KI = 0 dag 1 = 260x10 mal Volerome of solution = 106mla 1.061 = 0: 1062 Molasite = 260X10 mol = 24.53. Xo'm ca Scanne with 0.106 CamScanner