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Consider an hypothetical six-coordinate complex SHe with the sulfur atom located at the center of a trigonal prism as shown b

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Answer #1

SH6 :

(a) This molecule have Trigonal Prismatic geometry, as Sulfur is located at the center of trigonal prism (it is like 2-trigonal planar geometry attached to a point) ;

on using various symmetry operations it has : E;  2C3 (z) ; 3C'2 ; sigma.gifh (xy) ; 2S3 ; 3sigma.gifv symmetry elements , thus belongs to D3h point group.

D3h 2С3 3C2 дh Е 2S3 30v A1 1 1 1 -1 1 1 1 1 1 Rz A2 1 -1 2 -1 0 2 1 1 -2 1 1 1 1 0 1 1 x,y A 1 1 A21 2 1 1 -1 0 X,yz LLUJ

(b) Six H 1s orbitals in H6 framework in this molecule can be seen that how these are affected by each symmetry operations of D3h point group, to get symmetry of L.G.O.s.

D3h E 2C3 (z) 3C'2 sigma.gifh (xy) 2S3 3sigma.gifv
\Gamma6H(1s) 6 0 0 0 0 2

This representation can be reduced to irreducible representation :

A1’:1/12 [ (6x1x1) + (0x1x2) + (0x1x3) + (0x1x1) + (0x1x2) + (2x1x3) ] = 1/12[ 12 ] = 1

A2’: 1/12 [ (6x1x1) + (0x1x2) + (0x-1x3) + (0x1x1) + (0x1x2) +(2x-1x3) ] =1/12 [ 0 ]= 0

E’ : 1/12 [ (6x2x1) + (0x-1x2) + (0x0x3) + (0x2x1) + (0x-1x2) + (2x0x3) ] = 1/12 [ 12 ] = 1

A1”:1/12 [ (6x1x1) + (0x1x2) + (0x1x3) + (0x-1x1) + (0x-1x2) + (2x-1x3) ] = 1/12 [0 ]= 0

A2”: 1/12 [(6x1x1) +(0x1x2) +(0x-1x3) + (0x-1x1) + (0x-1x2) + (2x1x3) ] = 1/12 [ 12 ] = 1

E” : 1/12 [ (6x2x1) + (0x-1x2) + (0x0x3) + (0x-2x1) + (0x1x2) + (2x0x3) ] = 1/12 [ 12 ] = 1

\Gamma6H(1s) = A1’ + E’ + A2” + E”

Thus symmetries of LGOs =  a1’ + e’ +a2” + e”

(c) MO diagram for this can be constructed using valence orbitals of sulfur (3s and 3p) ; from character table symmetries : 3s ( a1’), 3px and 3py ( e’ ) and 3pz (a2” ).

3d (3p) tk a C3s) S evalence aitals Но SHE 342-3py (Dah) Triganal friahc M.D-Diagsam 1s

Non-bonding orbitals are shown higher in energy to account for possible interaction with 3d obitals.

(d) This molecule have 8 electrons in bonding orbital and 4 in non-bonding orbitals , thus overall bond order is 4 : it is for 6 S-H . Since it has bond order more than zero , thus this molecule can exist or occur, but its stabiilty will be less. For better explanation we shall include 3d orbitals into picture.There is greater ligand-ligand interaction :net repulsive, in this eclipsed geometry, thus making it less stable than Oh counterpart.

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