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Suppose you invest $1,000 in an account paying 6% interest per year. a. What is the balance in the account after 3 years? How
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Answer #1

1.
=Amount*(1+r)^t
=1000*1.06^3=1191.016

2.
=Amount*(1+r)^t-Amount*(1+r*t)
=1000*1.06^3-1000*(1+6%*3)=11.016

3.
=1000*1.06^25=4291.8707

4.
=1000*1.06^25-1000*(1+6%*25)=1791.8707

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