Question

Assuming an efficiency of 23.30%, calculate the actual yield of magnesium nitrate formed from 114.1 g of magnesium and excess copper(II) nitrate. Mg + Cu(NO), Mg(NO), + Cu actual yield:

Answer 1

solution: mg + cu (NO)2 -> Mg(NO3)2 + ca 114.19 moles af My = 14. 15 = 4.69 moles moles ay mg (N3formed4.69 moles Theoreticed yield ay mg (819 ) = 4.69X148.3 2 695.59 If effectency = 22.20% Then Actual yield of M7(0972: = 695-5 x 23:30 Actual yield = 34.559)