Suppose Coulomb measures a force of 2.0×10−5N between the two charged spheres when they are separated...
Suppose Coulomb measures a force of 2.0×10−5N between the two charged spheres when they are separated by 5.0cm . By turning the dial at the top of the torsion balance, he approaches the spheres so that they are separated by 3.0cm . What force does he measure now?
Homework Answers
From coulombs law
F= k*q1*q2/(r^2)
when they are separated by 5.0 cm
Finitial =k*q1*q2/(ri^2)
when they are separated by 3.0 cm
Ffinal =k*q1*q2/(rf^2)
Ffinal /(Finitial) =(ri^2)/(rf^2)
Ffinal = Finitial *(ri/rf)^2
= 2*10^-5 N *(5 cm/3 cm)^2
=5.6*10^-5 N
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