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A 0.250 kg mass is attached to a spring with k = 18.9 N/m. At the equilibrium position, it moves 2.89 m/s. What is the amplitude of the oscillation? (Unit = m) Enter
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Answer #1

Maximum spring energy = maximum kinetic energy

0.5 kA^2 = 0.5 mv^2

18.9*A^2 = 0.25 v^2

A = sqrt(0.25/18.9) *2.89 = 0.332 m answer

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