Consider reaction , Cu2S (s) 2 Cu + (aq) + S 2- (aq)
For above reaction, K sp = [ Cu + ] 2 [ S 2- ] = 1.0 10 -48 .
We know that, formation of solid takes place when Q = K sp.
Here , we have values of Q= K sp = 1.0 10 -48 & [ S 2- ] = 2.0 10 -15 . We need to calculate [ Cu + ] which is needed to begin precipitate.
we have , K sp = [ Cu + ] 2 [ S 2- ] = 1.0 10 -48
[ Cu + ] 2 = 1.0 10 -48 / [ S 2- ]
[ Cu + ] 2 = 1.0 10 -48 / 2.0 10 -15
[ Cu + ] 2 = 5.0 10 -34
[ Cu + ] = 2.2 10 -17 M
ANSWER : Concentration of Cu (I) needed to begin precipitation is 2.2 10 -17 M .
2. The Ksp of Cu2S is 1.0 x 10-48. What concentration of Cu+ (aq) is needed...
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