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2. The escape velocity for an object on the surface of the Earth is given by: 2GM = 1.12 x10 m/s VaR A projectile is launched
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Answer #1

ver=126 mg / kg ) as g = Gm / 22 Vese= VER = R 8/2g 2= V8 => R=(1:125 x1$ /ax 9-8 = 1.25x10€ /18:44 H =159 x10m 6 weight w=fg

m= (1.29-01 179)x200m3 = 1.118200 kg m=222.2kg for Hydrogen, m=(Palu) NH m=(1.29 -0.08)*/m3X200m3 = 242 kg (4) Force is given

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