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A 100 ml of 0.5M HCl was transferred into a 250 ml flask. In order to...

A 100 ml of 0.5M HCl was transferred into a 250 ml flask. In order to generate hydrogen gas, a 10.0 g sample of Zn was added to the acid, and the flask was immediately capped with balloon as shown in figure. Calculate the number of hydrogen gas molecules formed inside the balloon at 20°C.

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Answer #1

2ncl, t Zn +2Hu es Reacthion invelbet temt x e-5 molly x 0.05 mole Moler He adoled Man 2ine Moles 2n taken to q 65-38 g Imel

1 mol of H2 = 6.022 x 1023 molecules

0.025 mol of H2 = 6.022 x 1023 * 0.025

= ​​​​​1.505 x 1022 molecules of H2 (Answer)

P.S. Required amount of HCl to react completely with 0.153 mol of Zn will be 2*0.153 mol = 0.306 mol.

But, given amount of HCl is 0.05 mol, hence it is limiting reagent.

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