Two point charges lie on the x-axis: 1.60 μC at x = 1.00 m and –2.30 μC at x = 2.75 m . Part A Find the place(s) where the electric field is zero. Express your answer using two decimal places. If there is more than one answer, separate them by commas.
let us consider that point is to the left of 1.6 uC
at this point electric field due to q1 is equal to electric field due to q2
k q1 / d ^2 = k q2 / ( 1.75 + d )^2
sqrt (q2/q1) = 1.75/d + 1
sqrt ( 2.3/ 1.6) = 1.75/ d +1
d = 8.796 m
x co ordinate of this point = 1 - 8.796 = - 7.796 m
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Comment in case any doubt, will reply for sure. Goodluck
Two point charges lie on the x-axis: 1.60 μC at x = 1.00 m and –2.30...
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