Question

3. Determine the pH of a solution prepared by mixing 25.0 ml of a 0.10 mona solution with 50.0 ml of sodium hydroxide. (25 points) O.OSO M N prepared by mixing 25.0 ml of a 0.10 molar acetic acid OH NaOH = Na + OH Acetic And Kas18x10's

Answer 1

* 25 me of some of a a 0.10 m 0.050 m I CH₃COOH, ka=1.8 x 10-5 CH₂ CooH , kas nuon pH = I ? - solution; first find concentration of CH₂ cool and ot, mol MUCHCOOH. 0.025 lit. :.. [CH₂ cook] = mol = 0.10 m = 4 mol CH₃ Cout in Con Jamon = 0,050 M = 1 mol Olt 0.050 tit

so. The Balanced chemical equation for this Reaction is CH₂ cool cag + Naomlar, Ctz Coonaat coona + H₂ores (aq) - H2004) * Ionic equation o t 1 CH₂ cool cags & of caq, CH₂ coo caus" mol: Amore : 1 moleo - 1 13 + 3. .. - moel Acetic acid Remaining 3 moll Acetate Aetate - Total volime = 25 +50=75 me (0.075 lit) 40 find concen, of [cHg cock] =. mole = 3/5 = [cmycos)= macht in einem =) Henderson - Hesselbalch equation: pH = pka + log [cHg room] ... E CH₂ Co ch] like = 1,8X185 pH = 4.74 + log [ a to ] |-- Рka - - 1-3, Сke) Coments. Pka = -lo, Eli8x135) = 4.74 + log (1.6) . Pka = 4.74 pH = 4.74.to [PH = 4.74