Ans:
Test statistic:
t=((114.5-129.6)-(-10))/SQRT((5.06^2/5)+(5.37^2))
t=-0.88
df=5+5-2=8
p-value=tdist(0.88,8,1)=0.203
As,p-value>0.01,we fail to reject the null hypothesis.
Fail to reject H0.The data does not suggest that the difference between mean stopping distances is less than -10.
5. 11 points Previous Answers DevoreStat9 9..019. Per following datam- me 1145. e qeder o sh...
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