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An ionic compound, MBr, has ΔE for (M+1/2Br2 => MBr) = -500 kJ/mol. Given the information...

An ionic compound, MBr, has ΔE for (M+1/2Br2 => MBr) = -500 kJ/mol. Given the information below, calculate its lattice energy.

M(s) => M(g) ΔE = +140 kJ/mol

M(g) => M+(g) + 1 e- ΔE = +500 kJ/mol

Br2(l) => 2Br(g) ΔE = +200 kJ/mol

Br(g) + 1 e- => Br-(g) ΔE = -325 kJ

IE1 of Br(g) = +1143 kJ/mol

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Answer #1

Miss + £11 ) MBriss At = Dissecration sublimation AH, 1. energy B9718) Lattice energy Alte affinity obil. ig, t 192 electronstep-l: several steps M > Man AE = +140 k5lmol (S) sublima from step-2 Mos mtl the aq=+500 kilmos ionizatim energy B2 - 2B9 A

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