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1. The production function is given as 4m /3 and the cost of production is c = wx . The total revenue would be R=py or TR=4pr . The profit of the firm would be \pi = TR - c or 1/3 T4pr/ wr . The FOC for the maximization of the profit would be as below.

dr dr

or (4pr/-w) o

or 4/3)px 2/3w = 0

or 4/3)px 2/3

or x^{-2/3} = \frac{w}{(4/3) p}

or (4/3)p 2/3

or x^{2/3} = \frac{4 p}{3 w}

or x = \frac{4^{3/2} p^{3/2}}{3^{3/2} w^{3/2}}

or x^* = \frac{8 p^{3/2}}{3^{3/2} w^{3/2}} . This is the required demand for input x. This is the optimal level of x required given p and w.

2. The graph is as below, for p=1 and p=2.

ו 4 3 - K(p=1) \X(p=2) 2- Bו א 2 4 LO <ה צי ו ד בם זא]

As can be seen, as price increases (from 1 to 2 in this example), the input demand shifts right, meaning that the demand for input increases for all w's. Also, as we move from A to B, the wage decreases, but the input demand increases.

3. Putting the input demand in the production function, we have y = 4 \left (\frac{8 p^{3/2}}{3^{3/2} w^{3/2}} \right )^{1/3} or y = \frac{8 p^{1/2}}{3^{1/2} w^{1/2}} . The graph is below for w=2 and w=1.

10 8- 6 y(W-2) 4- y(w=1 2- В. A y 10 6 0O- גרם 00

As can be seen, as we move from point A to B, the price increases, and the output supply increases as well. Also, as wage decreases (from 2 to 1 in this example), the output supply increases for all level of p's.

4. The input demand for the given values would be x^* = \frac{8 * 24^{3/2}}{3^{3/2} 2^{3/2}} or x^* = \frac{64 *2^{3/2}*3^{3/2}}{3^{3/2} 2^{3/2}} or r= 64 units. The output would be y = \frac{8 *24^{1/2}}{3^{1/2} 2^{1/2}} or y = \frac{16 *2^{1/2} 3^{1/2}}{3^{1/2} 2^{1/2}} or y = 16 units. One may simply put x=64 in the production function also, to obtain same answer.

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