22) heat gain by iron = heat lost by water
mCiron(∆T) =mCwater(∆T)
20×0.449 ×(T-20) = 20×4.18×(80-T)
T = 74.2 °c
23) E = 164×103 /6 .022×1023
= 2.72×10-19 J
E = hC/wavelength
Wavelength = 6.626×10-34×3×108/2.72×10-19
=> 730 mm
24) Heat(q) = mS(∆T)
= 2.2×1000×4.18×(75.96-24.5)
= 473 kJ
∆H = -q
= -473 kJ
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