Question

Two equal charges are situated on the x axis at 40.0 cm on either side of the origin as shown in the figure below, Location A is on the perpendicular bisector at a distance of 22.0 cm from the origin on the y axis. (Assume that the +x axis is directed to the right and the ty axis is directed up.) 91 42 (a) If 91 =ー4.50 uc and q2 =-4.50 μC, what is the net electric field due to both charges at location A? Express your answer in vector form. N/C (b) If q1-4q2 (where q2-_4.50 μC), what is the net electric field at location A due to both charges? Express your answer in vector form. N/C

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Answer #1

we can calculate the electric field at point A by principle of superposition of electric field as solved below

Soluto: 22CM ey painciple een 2 2. EL ← 4.gd지6,le 7오, 시아 타ectic tie14- ne : 0.673 + E.sins-Eue^- Cj 5 5 1

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