Question

10. (a) Determine the mass of calcium oxide (CaO, lime) that can possibly be produced by heating 44.6 g of calcium carbonate (CaCO). The balanced equation for this reaction is shown in Equation 8 heat CaO(s) +CO2 (g) CaCOs(s) (Eq. 8) (b) Determine the mass of CO2 that would be produced by the reaction described in (a). 11. Joseph Priestley's study of the decomposition of mercury(ID oxide (HgO) with heat led to the discovery of O2. The balanced equation for this reaction is shown in Equation 9. heat 2 Hg()+02(g) 2 HgO(s) (Eq. 9) (a) How many grams of O2 could possibly be formed by the decomposition of 75.0 g of HgO? (b) How many grams of HgO must be decomposed to produce 75.0 g of O2? 12. Propane (CHg) is used as a fuel in many gas grills. The balanced equation for the combustion of CaHg is shown in Equation 10. CHs(g)+502(g)- 3 CO2 (g) +4H,O(g) +energy (Eq. 10) (a) How many grams of CO2 could possibly be produced if 10.0 g of CaHs reacts with an ample supply of O2? (b) How many grams of CO2 could possibly be produced with an ample supply of CaH, but only 10.0 g of O2? (c) If this reaction is run using 10.0 g of C3Hs and 10.0 g of O2, what mass of CO2 could possibly be produced? (d) Identify the limiting reagent in the reaction described in (c). 13. Tetraphosphorus decaoxide (P4O10) reacts with H2O to form H3PO4 The balanced equation for this reaction is shown in Equation 11. P4O10(s)+6H2O(e)-4H,PO4 (e) (Eq. 11) Calculate the mass of HsPO4 that could possibly be produced by the reaction of 300 g of P4O10 with 100 g of H2O. 14. Copper (Cu) dissolves in nitric acid (HNO), producing copper(II) nitrate, Cu(NOs)2 nitrogen dioxide (NO2), and H2O. The balanced equation for this reaction is shown in Equation 12 Cu(s)+4 HNOs(aq) Cu(NOs)2(aq)+2 NO2(g)+2 H2O() (Eq. 12)

Answer 1

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heat a o n CaCO3 (s1 A cao (s) + (02191 molar mass 100.0 t o 56.08 12 44.0 (ingimol) l mole of cacos produce I mole of cao 100.09 g of Cacos produce 56.08 g of Cao => 44.6 g of Cacos produce cau = 56.089 X 44.69 100099 = 24.999 25.09 Hence, 25.0g of cal will produce. b) 1 mole of cacos produce I mole of CO₂ 100.099 of Cocos produce 440 q Q 102 => 44.6 9 of colo's produce CO2 = 44.09 844.69 100.099 2 19.69 Hence, 19.0g of CO2 will produce