Question

82. I dissolve 30g of NaOH into 500mL of water. I add an indicator and I titrate into it 56.3mL of an unknown Molarity of HCI. What is the molarity of the HCl if 56.3 reached the equivalence point? (4pt)

Answer 1

solution 30 g NaOH = h . Molecular weight of moles MaoH - 40g moles in 500 me meam 102 moles in loco me £ 1.5M concentration

pone unknown molarity is S. volume of acid = 56.3 my volume of MaoH = 56,3 me Strength of Mach = 1.5m Now, VS, = Ng Sa s sa 1.5mx 56.3 m - 56.3 m 2 1.5M a Molarity of Hel in 1.5 m