Question

Pre-Lab Assignment for Experiment 19:Titration Curves Introduction: This pre-lab assignment will illustrate some of the important features of titration curves and what information can be obtained from them. A titration curve is the plot of the pH of a solution such as an acid or a base as a titrant is being added to it. A titrant is the solution being added from a buret, usually an acid or a base. In this assignment, we'll consider the titration of a 25.00 mL sample of HCl of unknown concentration with 0.115 M NaOH. The pH of the solution is of course measured with a pH meter. Our goal will be to determine the pH at the equivalence point and the concentration of our sample. What to Plot: Here's a table of sample data. ml NaOH added NaOH added 24 pH 27 29 29.1 9 12 13 14 pH 0.90 0.93 0.96 0.99 1.02 1.05 1.09 1.12 1.15 1.19 1.22 1.28 1.29 1.32 1.37 1.41 1.46 1.50 1.55 1.60 1.66 1.72 1.79 1.87 1.98 2.07 2.21 2.41 2.78 2.84 2.91 2.99 3.09 3.22 3.41 3.76 4.16 9.56 10.15 10.39 10.66 11.40 11.65 11.80 11.91 12 00 29.2 29.3 29.4 29.5 29.8 29.7 29.75 29.B 29.85 29.9 30 31 3 2 33 34 35 15 23 On the graph paper plot pH versus ml NaOH added. Choose the range of your axes carefully so that the plot fills the graph paper. The yaxis should be pH and the x-axis is ml NaOH.

If you could please help me with these that would be amazing! Thanks in advance

Answer 1

Ins. The chemical reaction that means by adding that NaOH occurs to during Head the the titration, following se action occurs. NOOH + Had - ward & Hoone 2 Ans; The amount of titrant is added to neutralise the solution in the wall beaker completely is called as equivalence point. It is the point of bitration, when the base and acids are strong, then the literation occurs in between them usually oquivalonce point will be at pH 7. Here we used strong acid Had and strong bose wooh. Hence the equivodenne point is pH 7 without doawing/ plotting geoph. By plotting graph it is around or near to pH & only. If you titrate a wook acid with a strong bose the salt produced is basic and the conjugale bose from the water. Hence salt reads with the solution produced is weakly pH of alkaline the equivolence and the point will be greater than 7. 3. Ans: The equivalence point on the graph is 70

Chart Tanks Microsoft Excel - 0 X Home Insert Page Layout Famulas Data Rp View Chemoffice Design Layout Format PirutTable Table Picture clip Shapes SmartArt Column Line Pie Bar Hyperlink Area Scatter Other - Charts 19 Tent Header WordArt Signature object Symbol Box Fouter Line Text Table 11.rations Charts Line Chart 1 Booki N O P Q R S T U V W HOI FI 0.9 0.93 0.96 0.99 1.02 1.05 1.09 1.12 1.15 1.19 1.26 pH on Y-axis Ph 1.29 1.32 1.37 1.41 1.46 1.5 1.55 ma SA 1.6 1.66 1.72 1.79 1.87 1.95 202 221 2.41 28 Sheet3 HEN Sheetl Sheet2 Ready Type here to search 0 Be 559 A 49 ENG 09-11-2019

3Ans: The equivalence point on the graph is 7.0 Ey Ans - 29.75 m is a required four to reach the equivalence point. SAN: How many moles of base does this many ml correspond is . molarity is the no. of moles of a substance in one litee of solution. M ewno. of moles Volume in lifees = MXV . We know waoH molarity 0.115m Volume = 35ML (OD 0.115 mol Nooh = 0.004025 moles 1L solution 0.035 L n = 0.035x * of wooh

Jaou Phi 0.9 0.93 0.96 0.99 1.02 1.05 1.09 1.12 1.15 1.19 1.22 1.26 1.29 1.32 1.37 1.41 1.46 1.5 1.55 1.6 pH on Y-axis WN NaOH in ml