Question
part b: what assumptions need to be made about this population?

part c: is there any evidence thag this proportion has changed since 2012 based on this sample ?

It was reported that 50% of individual tax returns were filed electronically in 2012. A random sample of 225 tax returns from
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ansi p=0.59, 8 - 7 - 153 = 0.68 a) Contodence Inselval - B z zelo I got. c. 1 0.68€ ).645 10.68*0.39 Y 295 = 0.68 + 0.0512 =

Add a comment
Know the answer?
Add Answer to:
part b: what assumptions need to be made about this population? part c: is there any...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • part b: What is the margin of error in this sample? part c: Is there any...

    part b: What is the margin of error in this sample? part c: Is there any evidence that this proportion has changed since 2012 based on this sample ? It was reported that 61% of individual tax returns were filed electronically in 2012. A random sample of 175 tax returns from 2013 was selected. From this sample, 111 were filed electronically. Complete parts a through c below. a. Construct a 90% confidence interval to estimate the actual proportion of taxpayers...

  • part b: what assumptions need to be about this population? Arandom sample of 15 college men's...

    part b: what assumptions need to be about this population? Arandom sample of 15 college men's basketball games during the last season had an average attendance of 5,085 with a sample standard deviation of 1,781. Complete parts a and below. a. Construct a 90% confidence interval to estimate the average attendance of a college men's basketball game during the last season The 99% confidence interval to estimate the average attendance of a college men's basketball game during the last season...

  • part b: what is the margin of error for this sample? part c: is there any...

    part b: what is the margin of error for this sample? part c: is there any evidence that this proportion has changed since 2008 based on this sample? According to a health organization in a certain country, 21.8% of the population smoked in 2008. In 2014, a random sample of 750 citizens of this country was selected, 141 of whom smoked. Complete parts a through c below. Nam a. Construct a 99% confidence interval to estimate the actual proportion of...

  • part b: What assumptions need to be made about this population ? A cruise company would...

    part b: What assumptions need to be made about this population ? A cruise company would like to estimate the average beer consumption to plan its beer inventory levels on future seven-day cruises. (The ship certainly doesn't want to run out of beer in the middle of the oceanl) The average beer consumption over 19 randomly selected seven-day cruises was 81,911 bottles with a sample standard deviation of 4,513 bottles. Complete parts a and b below a. Construct a 95%...

  • Q4) A national air traffic control system handled an average of 47,665 flights during 29 randomly...

    Q4) A national air traffic control system handled an average of 47,665 flights during 29 randomly selected days in a recent year. The standard deviation for this sample is 6,208 flights per day. Complete parts a through c below. a. Construct a 99​% confidence interval to estimate the average number of flights per day handled by the system. The 99​% confidence interval to estimate the average number of flights per day handled by the system is from a lower limit...

  • part b: what is the margin of error for this sample ? part c: is there any evidence that this proportion has changed si...

    part b: what is the margin of error for this sample ? part c: is there any evidence that this proportion has changed since 2009 based on this sample ? A website reported that 32% of drivers 18 and older admitted to texting while driving in 2009. In a random sample of 200 drivers 18 years and older drawn in 2010, 39 of the drivers said they texted while driving Complete parts a through c below a. Construct a 95%...

  • The following 5 questions are based on this information. In a random sample of 225 individual...

    The following 5 questions are based on this information. In a random sample of 225 individual tax returns in 2010, 72% ( = 0.72) were filed electronically. The goal is to construct a 90% confidence interval of the proportion (p) of all individual tax returns that were filed electronically in 2010. The standard error (SE) of p is Select one: O a. 0.05 O b. 0.20 O c.0.03 O d. 0.72 The critical value (CV) needed for the 90% confidence...

  • second part: What assumptions need to be made about this population? Construct a 95% confidence interval to estimat...

    second part: What assumptions need to be made about this population? Construct a 95% confidence interval to estimate the population mean using the data below, X = 22 s=4.8 n 18 What assumptions need to be made about this population? The 95% confidence interval for the population mean is from a lower limit of (Round to two decimal places as needed.)

  • part b. What assumptions need to be made to construct this interval? Golf cart attendants at...

    part b. What assumptions need to be made to construct this interval? Golf cart attendants at a local country Club often receive tips from golfers they assist with golf clubs. To help recruit new employees, the country club would like to determine the average tips per day an attendant eams. A sample of 14 attendants averaged $40.74 per day in tips. Assume the population standard deviation for daily tips is $8.72. Complete parts a and b below. a. Construct a...

  • part b: what assumptions need to be made about this population? 0.3.20-1 Question Help The following...

    part b: what assumptions need to be made about this population? 0.3.20-1 Question Help The following data show the number of hours per day 12 adults spent in front of screens watching television-related content Complete parts a and below. 1.4 4.7 3.8 4.8 74 6.50 5.6 2.1 5.2 1.8 29 8.1 a. Construct a 90% confidence interval to estimate the average number of hours per day adults spend in front of screens watching television-related content The 90% confidence interval to...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT