Question

Question 3 Not yet answered Marked out of 3.00 P Flag question How can chloride attack the positively charged carbocation (left), which is surrounded by sterically bulky methyl and ethyl groups? 10 + CH fast Select one or more: O a. The carbocation is now pyramidal, so the carbon is open to attack o b. The elactrostatic attraction between the positively-charged carbon and negatively charged chloride overcome steric considerations c. The positive charge on the carbon pushes the methyl and ethyl groups further away, so the carbon is open for attack O d. The carbocation is roughly planar, so the carbon is open to attack

Answer 1

As the starting material is carbocation having sp² hybridization so its geometry is trigonal planar now due to planarity surface above and below molecule is free from steric hinderence so + ve charge cation is attacked by negtive charge Nucleophile and alkyl halide product is formed

So Ans d the carbocation is roughly planar so thr carbon is open to attack

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