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In class, we showed the equation for electroosmotic mobility and electrophoretic mobility. Using these two equations, derive

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solution Given, electrophoretic mobality (Vep) = Me E electroesmatic mobality (Veo) = MeoE As we know, Tatal mobality (V totaSo from figure (Vtestal) cation > Vee (Vitatal) neutral = Vee (vitatal) anion < Veo from eq. Vtatal = Vep + Veo = Mere + leoeq. Am = l (Me + Meo) E As we know, magnitude of electric field (E) = ţ eq6 where, V= applied potential L = length of tube SuMe + lleo)v V katal = IL tm = (Met Meo) V

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