Calculate DH for the reaction BrCl(g) -----> Br(g) + Cl(g)
Given
Br2(l) -----> Br2(g) DH = 30.91 kJ
Br2(g) -----> 2Br(g) DH = 192.9 kJ
Cl2(g) ------> 2Cl(g) DH = 243.4 kJ
Br2(l) + Cl2(g) ----> 2BrCl(g) DH = 29.2 kJ
Lets number the reaction as 0, 1, 2, 3, 4 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 0 = +0.5 * (reaction 1) +0.5 * (reaction 2) +0.5 * (reaction 3) -0.5 * (reaction 4)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = +0.5 * ΔHo rxn(reaction 1) +0.5 * ΔHo rxn(reaction 2) +0.5 * ΔHo rxn(reaction 3) -0.5 * ΔHo rxn(reaction 4)
= +0.5 * (30.91) +0.5 * (192.9) +0.5 * (243.4) -0.5 * (29.2)
= 219.01 KJ
Answer: 219.01 KJ
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