Question

3.(adapted from Prob. 3, p. 103, Brown's Introductory Physics I) A baseball of mass m, is dropped at time t0 from rest (' 0) from the top of Alfred's Davis Memorial Carillon (which has height H) and falls freely under the influence of gravity. At the same instant (t 0), a second baseball of mass m, is thrown up from the ground directly below with speed vo2 (so if the second ball travels far enough, fast enough, they will collide).

Answer 1

Free body diagram of m_1 v_01 # free body diagram of m_2 v_02 notequalto 0 acceleration of m_1 = -g acceleration of m_2 = -g y_1 (t) = -1/2 gt^2 + H Y_2(t) = V_0 t - 1/2 gt^2 Y(t) is from the ground When two collide before hitting the ground when two don�t hit Y - distance from ground. \r\n when they just collide in the air then y_1(t) = y_2(t) -1/2 gt^2 + H = V_02 t - 1/2 gt^2 H = V_02 t when they just collide H = V_02 t 1 & V = 4 + at 0 = V_02 - gt t = V_02/g 2 by 1 & 2 20 = V_02 (V_02)/g V_02 = (20 times 9.81)^1/2 V_02 = 14.01 m/s V_02 = 31.37 miles per hour Answer velocity of m_2 must be greater than 31.37 miles/hr

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