a )
given
velociity is V = 95 kmph
or
V = 26.39 m/sec
t = 1 sec
a = - 4.5 m/sec2
xo = V x t
= 26.39 x 1
xo = 26.39 m
using equation to find d = u2 - V2 + 2 a xo / 2 a
= 02 - 26.392 + 2 x ( -4.5 ) x 26.39 / 2 x ( -4.5 )
d = - 26.392 + 2 x ( -4.5 ) x 26.39 / 2 x ( -4.5 )
= - 696.4321 - 237.51 / - 9
d = 103.771 m
b )
given
velociity is V = 95 kmph
or
V = 26.39 m/sec
t = 1 sec
b = - 6.7 m/sec2
xo = V x t
= 26.39 x 1
xo = 26.39 m
using equation to find d = u2 - V2 + 2 b xo / 2 b
= 02 - 26.392 + 2 x ( -6.7 ) x 26.39 / 2 x ( -6.7 )
d = - 26.392 + 2 x ( -6.7 ) x 26.39 / 2 x ( -6.7 )
= - 696.4321 - 353.626 / -13.4
d = 78.362 m
Determine the stopping distance for an automobile with an initial speed of 95km and human reaction...
Determine the stopping distances for an automobile with an initial speed of 95 km/h and human reaction time of 1.0 s : (a) for an acceleration a = -5.2 m/s2 , (b) for a = -6.6 m/s2 .
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