How would we work this out? I know the answer is 4.89
How would we work this out? I know the answer is 4.89 44) In the titration...
1) Calculate the pH in the titration of 50.00 mL of 0.060 M acetic acid (CH3COOH) with a 0.120 M sodium hydroxide, NaOH solution after the addition of the following volumes of base: Ka for acetic acid = 1.8 x 10-5 A) 0 mL pH = B) 10 ml pH =
Calculate the pH in the titration of 45.0 mL of 0.350 M accetic acid by sodium hydroxide after the addition to the acid solution of 10.5 mL of 0.250 M NaOH. The ka of acetic acid is 1.8 x 10^-5
A student is asked to determine the value of Ka for acetic acid by titration with potassium hydroxide. The student begins titrating a 46.4 mL sample of a 0.326 M aqueous solution of acetic acid with a 0.288 M aqueous potassium hydroxide solution, but runs out of standardized base before reaching the equivalence point. The student's last observation is that when 20.8 milliliters of potassium hydroxide have been added, the pH is 4.586. What is Ka for acetic acid based...
A student is asked to determine the value of Ka for acetic acid by titration with potassium hydroxide. The student begins titrating a 48.5 mL sample of a 0.598 M aqueous solution of acetic acid with a 0.305 M aqueous potassium hydroxide solution, but runs out of standardized base before reaching the equivalence point. The student's last observation is that when 64.8 milliliters of potassium hydroxide have been added, the pH is 5.041. What is Ka for acetic acid based...
A student is asked to determine the value of Ka for acetic acid by titration with barium hydroxide. The student begins titrating a 42.0 mL sample of a 0.594 M aqueous solution of acetic acid with a 0.253 M aqueous barium hydroxide solution, but runs out of standardized base before reaching the equivalence point. The student's last observation is that when 31.7 milliliters of barium hydroxidehave been added, the pH is 4.969. What is Ka for acetic acid based on...
In this assignment, you will calculate the pH of a solution during the course of a titration. The titration under study will be: 50 mL 0.5 M acetic acid (Ka = 1.8 x 10-5) is titrated with 0.25 M sodium hydroxide. a) Write a reaction for this titration b) Calculate the equivalence volume, and the pH at this point. c) Calculate the initial pH of the acetic acid solution Calculate the pH of the solution after d) 5 mL NaOH...
A student is asked to determine the value of Ka for hypochlorous acid by titration with sodium hydroxide. The student begins titrating a 34.2 mL sample of a 0.459 M aqueous solution of hypochlorous acid with a 0.453 M aqueous sodium hydroxide solution, but runs out of standardized base before reaching the equivalence point. The student's last observation is that when 21.9 milliliters of sodium hydroxide have been added, the pH is 7.665. What is Ka for hypochlorous acid based...
Consider a titration of 250 mL 0.15 M acetic acid (Ka = 1.8 x10-5) with 0.10 M KOH. What is the pH of the acetic acid solution (ie: before the titration has begun?) What is the pH after adding 25 mL of 0.10 M KOH? What is the volume of base needed to reach the equivalence point? Is the pH at equivalence point acidic, basic, or exactly neutral? What is the pH after 500 mL of KOH has been added?
Calculate the pH during the titration of 20.00 mL of 0.1000 M CH3COOH(aq) with 0.2000 M NaOH(aq) after 2.5 mL of the base have been added. Ka of acetic acid = 1.8 x 10-5. QUESTION 9 Calculate the pH during the titration of 30.00 mL of 0.1000 M ethylamine, C2H5NH2(aq), with 0.1000 M HCl(aq) after 26 mL of the acid have been added. Kb of ethylamine = 6.5 x 10-4. QUESTION 10 Calculate the pH during the titration of 20.00...
A) A 21.5 mL sample of a 0.452 M aqueous nitrous acid solution is titrated with a 0.356 M aqueous sodium hydroxide solution. What is the pH at the start of the titration, before any sodium hydroxide has been added? pH = B) A 42.1 mL sample of a 0.399 M aqueous acetic acid solution is titrated with a 0.219 M aqueous sodium hydroxide solution. What is the pH after 51.8 mL of base have been added? pH = C)...