Complete the following fusion reaction: 4He+3He⟶2H+−−−−−−.
Express your answer as a complete nuclear equation.
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Atomic number of missing particle,
n = (2 + 2) - 1 = 3
atomic mass of missing particle,
A.m = 4 + 3 - 2 = 5
so, particle is 3Li5 .
fusion reaction:
2He4 + 2He3 ⟶ 1H2 + 3Li5
Complete the following fusion reaction: 4He+3He⟶2H+−−−−−−. Express your answer as a complete nuclear equation. nothing SubmitRequest...
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Find the energy Q released in the fusion reaction. (Note that the reaction below is between nuclei. For the atomic masses, see this table. The mass of an electron is 0.00054 1H+3He → 4He + e+ + ν MeV Find the energy Q released in the fusion reaction. (Note that the reaction below is between nuclei. For the atomic masses, see this table. The mass of an electron is 0.00054 1H+3He → 4He + e+ + ν MeV
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