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On a 12 day wilderness expedition youll need to heat 3.0 kg of water to the boiling point each day. The air temperature will

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Answer #1

Mass of water needed to heat = 12day× 3.0kg/day = 36.Kg

∆T = 100-25.0 = 75.0℃

Heat required to boil desired water = m.s.∆T = 36.×103J×4.184J/g.℃ × 75℃ = 11296800J = 11296.8kJ

C3H8 +5 O2\rightarrow 3CO2 + 4H2O(l).   

∆H =enthalpy of formation of products - enthalpy of formation of reactants

= 3 × (-393.51) +4×(-285.83) - 5×0 - (-103.85) = -2220.kJ/mol

Number of propane in one canister = 75.g/44.1g/mol = 1.701mol

Amount of heat released by one canister = 2220kJ/mol× 1.701mol = 3775.5kJ

Number of canister required = 11296.8kJ/3775.5kJ/canister

= 2.993 canister

Minimum number of fuel canister needed = 3. canisters (Answer)

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