3)
Average speed = D/T = 68
D = 68 T ...... (1)
Distance = D = (T - 22/60) x 90.5 ....... (2)
Comparing (1) and (2)
68T = (T - 22/60) x 90.5 = 90.5T - 33.18
T = 1.47 hours
B)
Total distance = (1.47 - 22/60) x 90.5 = 100.27 km
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